The C++ Standard Library itself does not define a generic `release()` member function. However, the `release()` member function is part of certain types within the Standard Library. Here are some notable examples:
-
std::unique_ptr<T>::release()
-
std::basic_streambuf<CharT, Traits>::release()
- The
release()
member function exists in std::basic_streambuf
, which is a component of the input/output stream library.
- Purpose: Releases and returns a pointer to the internally managed buffer object.
- Example: Usage is rare and primarily involves custom stream buffer implementations.
Notes:
- Other libraries or frameworks may define their own
release()
functions, but these are not part of the standard library.
- If you encounter a
release()
function in code, check its context to understand its behavior, as it could be part of user-defined types or third-party libraries.
Here’s an implementation of the `release()` member function in the context of a singly linked list in C++17.
The `release()` function detaches the head node of the list and returns its pointer, leaving the rest of the list intact.
Implementation
#include
#include
// Node structure for the singly linked list
template
struct Node {
T data;
std::unique_ptr next;
Node(T value) : data(value), next(nullptr) {}
};
// Singly linked list implementation
template
class SinglyLinkedList {
private:
std::unique_ptr head;
public:
SinglyLinkedList() : head(nullptr) {}
// Function to add an element to the front of the list
void push_front(T value) {
auto newNode = std::make_unique(value);
newNode->next = std::move(head);
head = std::move(newNode);
}
// Function to release the head node
Node<T>* release() {
if (!head) {
return nullptr; // If the list is empty, return nullptr
}
Node<T>* rawHead = head.release(); // Release ownership of the head node
head = std::move(rawHead->next); // Update head to the next node
return rawHead;
}
// Function to print the list
void print() const {
Node<T>* current = head.get();
while (current) {
std::cout << current->data << " -> ";
current = current->next.get();
}
std::cout << "nullptr" << std::endl;
}
// Destructor to clean up the list
~SinglyLinkedList() {
while (head) {
head = std::move(head->next);
}
}
};
int main() {
SinglyLinkedList list;
// Add some elements to the list
list.push_front(10);
list.push_front(20);
list.push_front(30);
std::cout << "Original list: ";
list.print();
// Release the head node
Node* releasedNode = list.release();
if (releasedNode) {
std::cout << "Released node: " << releasedNode->data << std::endl;
delete releasedNode; // Manually delete the released node
}
std::cout << "List after release: ";
list.print();
return 0;
}
Explanation
-
Node
Structure:
- Represents each node of the singly linked list, with a data value and a
next
pointer.
-
push_front
Method:
- Adds a new element to the front of the list.
-
release
Method:
- Detaches the head node by calling
release()
on the std::unique_ptr
managing it.
- Updates the head of the list to the next node.
- Returns a raw pointer to the detached node.
-
print
Method:
- Traverses and prints the list.
-
main
Function:
- Demonstrates creating a list, adding elements, releasing the head node, and printing the list before and after the release.
Output
Original list: 30 -> 20 -> 10 -> nullptr
Released node: 30
List after release: 20 -> 10 -> nullptr
This implementation showcases how `std::unique_ptr` and its `release()` function can be applied to manage dynamic memory in a singly linked list.
The
release
function is used to return all list elements to free store. It marches down the list doing so.
//elements returned to free store
void slist::release()
{
while (h != 0)
del();
}
Each element of the list should be returned to free store in sequence. This is done for a single element by
slist::del()
, which manipulates the hidden pointer
h
. Since we are destroying the list, it is unnecessary to preserve the original value of pointer
h
. This function's chief use is as the body of the destructor
slist::~slist()
. We could not use a destructor written
slist::~slist()
{
delete h;
}
because it deletes only the first element in the list.