The problem with using
void* is that it cannot be dereferenced. Thus, to perform useful work on a generic pointer, you must cast it to a standard working type, such as
char*.
- Instructions
Use the following code fragment to write and test the memcpy function so that the generic pointer type is cast to char*.
This function copies the n characters from the variable based at s2 into the variable based at s1 and works with any two pointer types as actual arguments.
C++ Code
void* memcpy(void* s1, const void* s2, unsigned n){
char* from = s2, *to = s1; //uses char type
....
}
Note that in addition to using
void* as the generic pointer type, the function uses
void* as the return type.
Paste the source code of the function below and click the
Submit
button when you are ready to submit this exercise.